50-12x^2=23

Solution for 50-12x^2=23 equation:

50-12x^2=23

We move all terms to the left:

50-12x^2-(23)=0

We add all the numbers together, and all the variables

-12x^2+27=0

a = -12; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-12)·27
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-12}=\frac{-36}{-24}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-12}=\frac{36}{-24}
=-1+1/2
$